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64.最小路径和.js
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64.最小路径和.js
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/*
* @lc app=leetcode.cn id=64 lang=javascript
*
* [64] 最小路径和
*/
// @lc code=start
/**
* @param {number[][]} grid
* @return {number}
*/
// const { createPrinter } = require('./utils/index')
// const printer = createPrinter()
// dp[i][j] = Math.min(grid[i-1][j], grid[i][j-1])
// solution1:
// var minPathSum = function(grid) {
// const n = grid.length
// const m = grid[0].length
// let memo = new Array(n).fill(-1).map(() => new Array(m).fill(-1))
// let res = dp(grid, n - 1, m - 1)
// return res
// function dp(grid, i, j) {
// if (i === 0 && j === 0) {
// return grid[0][0]
// }
// if (i < 0 || j < 0) {
// return Infinity
// }
// if (memo[i][j] !== -1) {
// return memo[i][j]
// }
// memo[i][j] = Math.min(dp(grid, i - 1, j), dp(grid, i, j - 1)) + grid[i][j]
// return memo[i][j]
// }
// }
// solution2
var minPathSum = function(grid) {
let n = grid.length
let m = grid[0].length
let dp = new Array(n).fill(0).map(() => new Array(m).fill(0))
dp[0][0] = grid[0][0]
// base case, i && j should start with index 1
for (let i = 1; i < n; i++) {
// ! do not mess dp with grid
dp[i][0] = dp[i - 1][0] + grid[i][0]
}
for (let j = 1; j < m; j++) {
dp[0][j] = dp[0][j - 1] + grid[0][j]
}
for (let i = 1; i < n; i++) {
for (let j = 1; j < m; j++) {
dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]
}
}
return dp[n - 1][m - 1]
}
// @lc code=end
module.exports = { minPathSum }