Scan Integer with leading zero?

[MaxMxMz]

Hello!
integer data - 01 02 0003 and so on ..... with leading zero

I Use example
int main()
{
char8_t a,b,c,d;
scan(a,".",b,".",c,".",d);
println(a,".",b,".",c,".",d);
}
if i enter 01.2.3.4 - i have exeption

I've tried
scan("0", a); - work,
but when data no have leading zero, i have exeption

[trcrsired]

Hi. This needs to use manipulator ::fast_io::manipulator::base_get<10, false, true>(a)

i have just found it only has bin_get and hex_get so i am adding dec_get and oct_get. so you can use ::fast_io::manipulator::dec_get<false, true>(a) instead

template <::std::size_t bs, bool noskipws = false, bool skipzero = false, bool prefix = false, ::fast_io::details::my_integral scalar_type>
inline constexpr scalar_manip_t<::fast_io::details::base_scan_mani_flags_cache<bs, noskipws, (bs == 10 ? false : prefix), skipzero>,
								scalar_type &>
base_get(scalar_type &t) noexcept
{
	return {t};
}

template <bool noskipws = false, bool skipzero = false, ::fast_io::details::my_integral scalar_type>
inline constexpr scalar_manip_t<::fast_io::details::base_scan_mani_flags_cache<10, noskipws, false, skipzero>,
								scalar_type &>
dec_get(scalar_type &t) noexcept
{
	return {t};
}

The reason zeros are not skipped by default is that numbers starting with a 0 might be interpreted as octal (base 8) numbers, causing issues for things like IP addresses. This is an unfortunate consequence from UNIX.

Scanning with a string literal isn't meant for any kind of string pattern matching. It only means that next part of string in the stream must be that string. fast_io does not use any kind of format string at all.

[trcrsired]

BTW, in your example i think you need to set noskipws to be true too so it cannot skip spaces