Skip to content

Latest commit

 

History

History
277 lines (261 loc) · 8.31 KB

123.md

File metadata and controls

277 lines (261 loc) · 8.31 KB

Results of GPT-4 on HumanEval/123

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 257

def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """if n%2==0:
        odd_collatz = [] 
    else:
        odd_collatz = [n]
    while n > 1:
        if n % 2 == 0:
            n = n/2
        else:
            n = n*3 + 1
            
        if n%2 == 1:
            odd_collatz.append(int(n))

    return sorted(odd_collatz)

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(14) == [1, 5, 7, 11, 13, 17]
    assert candidate(5) == [1, 5]
    assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == [1], "This prints if this assert fails 2 (also good for debugging!)"

Runs

✅ Run 1

Start time: 2023-07-18 18:03:07
Duration: 7.61s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)

✅ Run 2

Start time: 2023-07-18 18:02:57
Duration: 9.64s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [number for number in collatz_sequence if number % 2 != 0]
    return sorted(odd_numbers)

✅ Run 3

Start time: 2023-07-18 18:02:50
Duration: 7.61s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)

✅ Run 4

Start time: 2023-07-18 18:02:39
Duration: 10.31s
Completion tokens: 95
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_collatz = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_collatz)

✅ Run 5

Start time: 2023-07-18 18:02:32
Duration: 7.74s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)

✅ Run 6

Start time: 2023-07-18 18:02:11
Duration: 21.02s
Completion tokens: 296
Result: Pass

def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    collatz_sequence = []
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            collatz_sequence.append(n)
            n = 3 * n + 1
    collatz_sequence.append(1)
    return sorted(collatz_sequence)

✅ Run 7

Start time: 2023-07-18 18:02:00
Duration: 9.99s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)

✅ Run 8

Start time: 2023-07-18 18:01:52
Duration: 8.07s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)

✅ Run 9

Start time: 2023-07-18 18:01:27
Duration: 25.52s
Completion tokens: 296
Result: Pass

def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    collatz_sequence = []
    while n != 1:
        if n % 2 == 0:
            n = n / 2
        else:
            collatz_sequence.append(n)
            n = 3 * n + 1
    collatz_sequence.append(1)
    return sorted(collatz_sequence)

✅ Run 10

Start time: 2023-07-18 18:01:19
Duration: 7.53s
Completion tokens: 93
Result: Pass

def get_odd_collatz(n):
    collatz_sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz_sequence.append(n)
    odd_numbers = [num for num in collatz_sequence if num % 2 != 0]
    return sorted(odd_numbers)